# PSEB Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.2

PSEB Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.2

## PSEB 10th Class Maths Solutions Chapter 6 Triangles Ex 6.2

Question 1.

In fig. (i) and (ü), DE U BC. Find EC in (i) and AD in (ii).

Question 2.

E and F are points on the sides PQ and PR respectively of a APQR. For each of the following cases, state whether EF || QR :

(i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm

(ii) PE =4 cm, QE = 4.5 cm, PF =8 cm and RF = 9cm.

(iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm.

Solution:

In ∆PQR, E and F are two points on side PQ and PR respectively.

Hence proved.

Question 5.

In fig. DE || OQ and DF || OR. Show that EF || QR.

Question 6.

In flg., A, B and C points on OP, OQ and OR respectively such that AB || PQ and AC || PR. Show thatBC || QR.

Question 7.

Using Basic Proportionality theorem, prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side. (Recall that you have proved ¡t in class IX).

Solution:

Given: In ∆ABC, D is mid point of AB, i.e. AD = DB.

A line parallel to BC intersects AC at E as shown in figure. i.e., DE || BC.

Question 8.

Using converse of Basic Proportionality theorem prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side. (Recall that you have done ¡tin Class IX).

Solution:

Given ∆ABC, D and E are mid points of AB and AC respectively such that AD = BD and AE = EC, D and Eare joined

∴ By using converse of basic

proportionlity Theorem,

EO || DC also EO || AB [Const]

⇒ AB || DC

∴ Quadrilateral ABCD is a trapezium with AB || CD.

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